\(\frac{4\cdot7}{9\cdot32}=\frac{4\cdot7}{9\cdot8\cdot4}=\frac{7}{8\cdot9}=\frac{7}{72}\)

\(\frac{2\cdot5\cdot13}{26\cdot35}=\frac{2\cdot5\cdot13}{2\cdot13\cdot7\cdot5}=\frac{1}{7}\)

\(\frac{3\cdot21}{14\cdot15}=\frac{3\cdot3\cdot7}{2\cdot7\cdot3\cdot5}=\frac{3}{2\cdot5}=\frac{3}{10}\)

\(\frac{9\cdot6-9\cdot3}{18}=\frac{9\cdot\left(6-3\right)}{9\cdot2}=\frac{9\cdot3}{9\cdot2}=\frac{3}{2}\)

\(\frac{17\cdot5-17}{3-20}=\frac{17\cdot\left(5-1\right)}{-17}=\frac{17\cdot4}{17\cdot\left(-1\right)}=\frac{4}{-1}=-4\)

\(45dm^2=0,45m^2\)

\(300cm^2=0,03m^2\)

\(57500mm^2=0,0575m^2\)

a, \(\frac{4.7}{9.32}\)= \(\frac{7}{9.8}\)=\(\frac{7}{72}\) 

54

ủng hộ mk đi các bạn

chao ôi , mk chưa học

a) \(\dfrac{{50}}{{85}}\) 

Ta có: \(50 =2.5^2; 85= 5.17\)

Thừa số nguyên tố chung là 5 với số mũ nhỏ nhất là 1 nên ƯCLN(50, 85) = 5. Do đó, \(\dfrac{{50}}{{85}}\) chưa là phân số tối giản

Ta có: \(\dfrac{{50}}{{85}} = \dfrac{{50:5}}{{85:5}} = \dfrac{{10}}{{17}}\)

b)\(\dfrac{{23}}{{81}}\)

Ta có: \(23 = 23; 81 = 3^4\)

Chúng không có thừa số nguyên tố chung nên ƯCLN(23, 81) = 1. Do đó, \(\dfrac{{23}}{{81}}\) là phân số tối giản.

a) $\frac{4.7}{9.32}=\frac{4.7}{\mathrm{9.4.8}}=\frac{7}{9.8}=\frac{7}{72}$

b) $\frac{3.21}{14.15}=\frac{\mathrm{3.3.7}}{\mathrm{2.7.3.5}}=\frac{3}{2.5}=\frac{3}{10}$

c) $\frac{\mathrm{2.5.13}}{26.35}=\frac{\mathrm{2.5.13}}{\mathrm{2.13.5.7}}=\frac{1}{7}$

d) $\frac{9.6–9.3}{18}=\frac{9.(6–3)}{9.2}=\frac{6–3}{2}=\frac{3}{2}$

e) $\frac{17.5–17}{3–20}=\frac{17.(5–1)}{–17}=\frac{5–1}{–1}=–4$

f) $\frac{49+7.49}{49}=\frac{49.(1+7)}{49}=1+7=8$

a) \(\dfrac{4.7}{9.32}=\dfrac{4.7}{9.4.8}=\dfrac{7}{72}\)

b) \(\dfrac{3.21}{14.15}=\dfrac{3.3.7}{2.7.3.5}=\dfrac{3}{10}\)

c) \(\dfrac{2.5.13}{26.35}=\dfrac{2.5.13}{2.13.5.7}=\dfrac{1}{7}\)

d) \(\dfrac{9.6-9.3}{18}=\dfrac{9\left(6-3\right)}{9.2}=\dfrac{3}{2}\)

e) \(\dfrac{17.5-17}{3-20}=\dfrac{17\left(5-1\right)}{-17}=\dfrac{5-1}{-1}=-4\)

f) \(\dfrac{49+7.49}{49}=\dfrac{49\left(1+7\right)}{49}=8\)

Trả lời:

A: \(\frac{84}{180}=\frac{7}{15}\)

B: \(\frac{154}{322}=\frac{11}{23}\)

C: \(\frac{234}{790}=\frac{117}{395}\)

D;\(\frac{198}{814}=\frac{9}{37}\)

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a) \(\dfrac{8}{16}=\dfrac{8:8}{16:8}=\dfrac{1}{2}\)

b) \(\dfrac{10}{30}=\dfrac{10:10}{30:10}=\dfrac{1}{3}\)

c) \(\dfrac{24}{18}=\dfrac{24:6}{18:6}=\dfrac{4}{3}\)

d) \(\dfrac{20}{28}=\dfrac{20:4}{28:4}=\dfrac{5}{7}\)

Giải:

a) \(\dfrac{5^3.90.4^3}{25^2.3^2.2^{13}}\) 

\(=\dfrac{5^3.5.3^2.2.\left(2^2\right)^3}{\left(5^2\right)^2.3^2.2^{13}}\) 

\(=\dfrac{5^4.3^2.2.2^6}{5^4.3^2.2^{13}}\) 

\(=\dfrac{5^4.3^2.2^7}{5^4.3^2.2^{13}}\) 

\(=\dfrac{1}{2^6}=\dfrac{1}{64}\) 

b) \(\dfrac{15^2.16^4-15^3.16^3}{12^2.20^3-20^2.12^3}\) 

\(=\dfrac{15^2.16^3.16-15^2.16^3.15}{12^2.20^2.20-20^2.12^2.12}\) 

\(=\dfrac{15^2.16^3.\left(16-15\right)}{12^2.20^2.\left(20-12\right)}\) 

\(=\dfrac{\left(3.5\right)^2.\left(2^4\right)^3.1}{\left(3.2^2\right)^2.\left(2^2.5\right)^2.8}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.\left(2^2\right)^2.\left(2^2\right)^2.5^2.2^3}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.5^2.2^4.2^4.2^3}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.5^2.2^{11}}\) 

\(=2\) 

c) \(\dfrac{2.3+4.6+14.21}{3.5+6.10+21.35}\) 

\(=\dfrac{2.3+2.3.2.2+2.3.7.7}{3.5+3.5.2.2+3.5.7.7}\) 

\(=\dfrac{2.3+2.3.4+2.3.49}{3.5+3.5.4+3.5.49}\) 

\(=\dfrac{2.3.\left(1+4+49\right)}{3.5.\left(1+4+49\right)}\) 

\(=\dfrac{2.3}{3.5}\) 

\(=\dfrac{2}{5}\) 

Chúc bạn học tốt!

giúp mình với, đi mà mọi người mình đang cần gấp mà

a) 2/3,1/4,1/2,21/44
b) 2/3,3/5,1/8,1/3

\(\frac{4.7}{9.32}=\frac{1.7}{9.8}=\frac{7}{72}\)

=\(\frac{4.7}{9.4.8}=\frac{7}{72}\)